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Determine whether the values 3 and 4 are solutions to the quadratic equation x2−7x+12=0 , and then select the correct answer fr...Asked by x
Determine whether the values 3 and 4 are solutions to the quadratic equation x^2−7x+12=0
, and then select the correct answer from the following options.
Option #1: Only x=3
is a solution.
Option #2: Only x=4
is a solution.
Option #3: Both x=3
and x=4
are solutions.
Option #4: Neither x=3
nor x=4
is a solution.
(1 point)
, and then select the correct answer from the following options.
Option #1: Only x=3
is a solution.
Option #2: Only x=4
is a solution.
Option #3: Both x=3
and x=4
are solutions.
Option #4: Neither x=3
nor x=4
is a solution.
(1 point)
Answers
Answered by
x
x Substituted Evaluate True Statement?
−23
0
12
For the quadratic equation x2+20x=69
, complete the table by testing each of the given values to determine whether it is a solution. Identify which one of these values is in the solution set.
(1 point)
Only x= ( )
is in the solution set.
−23
0
12
For the quadratic equation x2+20x=69
, complete the table by testing each of the given values to determine whether it is a solution. Identify which one of these values is in the solution set.
(1 point)
Only x= ( )
is in the solution set.
Answered by
GPT-4o mini
To determine whether 3 and 4 are solutions to the quadratic equation \( x^2 - 7x + 12 = 0 \), we can substitute each value into the equation and check if each results in equality.
1. **Substituting \( x = 3 \)**:
\[
(3)^2 - 7(3) + 12 = 9 - 21 + 12 = 0
\]
Since the left side equals 0, \( x = 3 \) is a solution.
2. **Substituting \( x = 4 \)**:
\[
(4)^2 - 7(4) + 12 = 16 - 28 + 12 = 0
\]
Since the left side equals 0, \( x = 4 \) is also a solution.
Thus, both \( x = 3 \) and \( x = 4 \) are solutions to the equation.
The correct answer is:
**Option #3: Both \( x = 3 \) and \( x = 4 \) are solutions.**
1. **Substituting \( x = 3 \)**:
\[
(3)^2 - 7(3) + 12 = 9 - 21 + 12 = 0
\]
Since the left side equals 0, \( x = 3 \) is a solution.
2. **Substituting \( x = 4 \)**:
\[
(4)^2 - 7(4) + 12 = 16 - 28 + 12 = 0
\]
Since the left side equals 0, \( x = 4 \) is also a solution.
Thus, both \( x = 3 \) and \( x = 4 \) are solutions to the equation.
The correct answer is:
**Option #3: Both \( x = 3 \) and \( x = 4 \) are solutions.**
Answered by
GPT-4o mini
To determine whether the values -23, 0, and 12 are solutions to the quadratic equation \(x^2 + 20x = 69\), we first rewrite the equation in standard form:
\[
x^2 + 20x - 69 = 0
\]
Now we will substitute each value into the left side of the equation and see if it equals 0.
1. **Substituting \(x = -23\)**:
\[
(-23)^2 + 20(-23) - 69 = 529 - 460 - 69 = 0
\]
This simplifies to:
\[
529 - 460 - 69 = 529 - 529 = 0
\]
So, \(x = -23\) is a solution.
2. **Substituting \(x = 0\)**:
\[
(0)^2 + 20(0) - 69 = 0 + 0 - 69 = -69
\]
This does not equal 0, so \(x = 0\) is not a solution.
3. **Substituting \(x = 12\)**:
\[
(12)^2 + 20(12) - 69 = 144 + 240 - 69 = 144 + 240 - 69 = 315
\]
This does not equal 0, so \(x = 12\) is not a solution.
Now we compile the results:
- **For \(x = -23\)**: True (it equals 0)
- **For \(x = 0\)**: False (it does not equal 0)
- **For \(x = 12\)**: False (it does not equal 0)
Thus, the only value that is in the solution set is:
**Only \(x = -23\) is in the solution set.**
\[
x^2 + 20x - 69 = 0
\]
Now we will substitute each value into the left side of the equation and see if it equals 0.
1. **Substituting \(x = -23\)**:
\[
(-23)^2 + 20(-23) - 69 = 529 - 460 - 69 = 0
\]
This simplifies to:
\[
529 - 460 - 69 = 529 - 529 = 0
\]
So, \(x = -23\) is a solution.
2. **Substituting \(x = 0\)**:
\[
(0)^2 + 20(0) - 69 = 0 + 0 - 69 = -69
\]
This does not equal 0, so \(x = 0\) is not a solution.
3. **Substituting \(x = 12\)**:
\[
(12)^2 + 20(12) - 69 = 144 + 240 - 69 = 144 + 240 - 69 = 315
\]
This does not equal 0, so \(x = 12\) is not a solution.
Now we compile the results:
- **For \(x = -23\)**: True (it equals 0)
- **For \(x = 0\)**: False (it does not equal 0)
- **For \(x = 12\)**: False (it does not equal 0)
Thus, the only value that is in the solution set is:
**Only \(x = -23\) is in the solution set.**
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