To solve \( \frac{38}{15} - \frac{4}{3} \), we need to find a common denominator.
The denominator of \( \frac{38}{15} \) is 15, and the denominator of \( \frac{4}{3} \) is 3. The least common multiple of 15 and 3 is 15.
Next, we will convert \( \frac{4}{3} \) to a fraction with a denominator of 15:
\[ \frac{4}{3} = \frac{4 \times 5}{3 \times 5} = \frac{20}{15} \]
Now we can rewrite the equation:
\[ \frac{38}{15} - \frac{20}{15} \]
Now that both fractions have the same denominator, we can subtract them:
\[ \frac{38 - 20}{15} = \frac{18}{15} \]
We can simplify \( \frac{18}{15} \) by dividing both the numerator and the denominator by 3:
\[ \frac{18 \div 3}{15 \div 3} = \frac{6}{5} \]
Thus, the final answer is:
\[ \frac{6}{5} \]