From the Periodic table, it can be determined that iron (Fe) has an atomic mass of 56 amu, oxygen (O) has an atomic mass of 16 amu, and hydrogen (H) has a mass of 1 amu. What would the atomic mass of Fe(OH) 3 be?(1 point)

Question

Responses

107 amu
107 amu

73 amu
73 amu

219 amu
219 amu

75 amu

Answer 1

To calculate the atomic mass of Fe(OH)₃, we need to consider the contributions of each element in the compound:

1. Iron (Fe): 1 atom x 56 amu = 56 amu
2. Oxygen (O): 3 atoms x 16 amu = 48 amu (since there are 3 OH groups, and each has one oxygen)
3. Hydrogen (H): 3 atoms x 1 amu = 3 amu (since there are 3 OH groups, and each has one hydrogen)

Now, we can sum these contributions together:

\[ \text{Total mass} = \text{mass of Fe} + \text{mass of O} + \text{mass of H} \] \[ \text{Total mass} = 56, \text{amu} + 48, \text{amu} + 3, \text{amu} = 107, \text{amu} \]

So, the atomic mass of Fe(OH)₃ is 107 amu.