Question
The question is what is the molecular equation for acetic acid mixed with ammonia, sulfuric acid mixed with barium hydroxide, copper (II) sulfate mixed with hydrosulfuric acid, and copper (II) acetate mixed with hydrosulfuric acid. I've attempted some but for the last two i have no clue.
a) CH3OOH (aq) + NH3 (aq) --> NH4(aq) + CH3C00
b) Ba(OH)2 (aq) + H2SO4 (aq) --> BaSO4 (aq) + 2H2O (l)
c) CuSO4 (aq) + H2S (aq) --> ??
D) Cu(CH3OO)2 (aq) + H2S --> ??
a) CH3OOH (aq) + NH3 (aq) --> NH4(aq) + CH3C00
b) Ba(OH)2 (aq) + H2SO4 (aq) --> BaSO4 (aq) + 2H2O (l)
c) CuSO4 (aq) + H2S (aq) --> ??
D) Cu(CH3OO)2 (aq) + H2S --> ??
Answers
The question is what is the molecular equation for acetic acid mixed with ammonia, sulfuric acid mixed with barium hydroxide, copper (II) sulfate mixed with hydrosulfuric acid, and copper (II) acetate mixed with hydrosulfuric acid. I've attempted some but for the last two i have no clue.
a) CH3OOH (aq) + NH3 (aq) --> NH4(aq) + CH3C00
<b>The question asks for molecular equation. You wrote an ionic equation.</b>
b) Ba(OH)2 (aq) + H2SO4 (aq) --> BaSO4 (aq) + 2H2O (l)
<b>OK</b>
c) CuSO4 (aq) + H2S (aq) --> ??
<b>CuS + H2SO4. You need to learn the solubility tables. " target="_blank">http://www.files.chem.vt.edu/RVGS/ACT/notes/solubility_rules.html</b>
D) Cu(CH3OO)2 (aq) + H2S --> ??
<b>CuS + 2CH3COOH</b>
a) CH3OOH (aq) + NH3 (aq) --> NH4(aq) + CH3C00
<b>The question asks for molecular equation. You wrote an ionic equation.</b>
b) Ba(OH)2 (aq) + H2SO4 (aq) --> BaSO4 (aq) + 2H2O (l)
<b>OK</b>
c) CuSO4 (aq) + H2S (aq) --> ??
<b>CuS + H2SO4. You need to learn the solubility tables. " target="_blank">http://www.files.chem.vt.edu/RVGS/ACT/notes/solubility_rules.html</b>
D) Cu(CH3OO)2 (aq) + H2S --> ??
<b>CuS + 2CH3COOH</b>
I need to make a correction. The BaSO4 shown in the middle question <b>is a solid) and should be written as BaSO4(s)</b>
I see then for part a) would the molecular qwuation be CH3COOH + NH3 --> NH4CH3OO. Thanks for the link it really help as well as the help itself.
Yes, the molecular equation is right; usually it is written as CH3COONH4 but what you wrote is not incorrect. Note the correction I made in the solubility of BaSO4. I didn't notice you had (aq) by it.
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