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Original Question
solve the followinh quadratic equation using square roots: (c+36)^2 - 38 = 251Question
solve the following quadratic equation using square roots: (X+36)^2 - 38 = 251
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Answered by
GPT-4o mini
To solve the quadratic equation \((X + 36)^2 - 38 = 251\) using square roots, we first need to isolate the squared term. Here are the steps to solve the equation:
1. Start with the original equation:
\[
(X + 36)^2 - 38 = 251
\]
2. Add 38 to both sides to isolate the squared term:
\[
(X + 36)^2 = 251 + 38
\]
\[
(X + 36)^2 = 289
\]
3. Now, take the square root of both sides:
\[
X + 36 = \pm \sqrt{289}
\]
4. Since \(\sqrt{289} = 17\), we have:
\[
X + 36 = 17 \quad \text{or} \quad X + 36 = -17
\]
5. Now, solve for \(X\) in both cases:
- For \(X + 36 = 17\):
\[
X = 17 - 36 = -19
\]
- For \(X + 36 = -17\):
\[
X = -17 - 36 = -53
\]
6. Thus, the solutions to the quadratic equation are:
\[
X = -19 \quad \text{and} \quad X = -53
\]
The final answer is:
\[
X = -19 \quad \text{or} \quad X = -53
\]
1. Start with the original equation:
\[
(X + 36)^2 - 38 = 251
\]
2. Add 38 to both sides to isolate the squared term:
\[
(X + 36)^2 = 251 + 38
\]
\[
(X + 36)^2 = 289
\]
3. Now, take the square root of both sides:
\[
X + 36 = \pm \sqrt{289}
\]
4. Since \(\sqrt{289} = 17\), we have:
\[
X + 36 = 17 \quad \text{or} \quad X + 36 = -17
\]
5. Now, solve for \(X\) in both cases:
- For \(X + 36 = 17\):
\[
X = 17 - 36 = -19
\]
- For \(X + 36 = -17\):
\[
X = -17 - 36 = -53
\]
6. Thus, the solutions to the quadratic equation are:
\[
X = -19 \quad \text{and} \quad X = -53
\]
The final answer is:
\[
X = -19 \quad \text{or} \quad X = -53
\]
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