Use the image to answer the question.

To determine whether the points (0, 2) and (0, -4) are solutions to the system of equations \( y = 2x + 2 \) and \( y = 2x - 4 \), we can substitute the x-values of each point into both equations and see if the corresponding y-values match.

1. For the point (0, 2):

- Substituting \( x = 0 \) in the first equation \( y = 2x + 2 \):
\[
y = 2(0) + 2 = 0 + 2 = 2
\]
This point lies on the first equation.

- Substituting \( x = 0 \) in the second equation \( y = 2x - 4 \):
\[
y = 2(0) - 4 = 0 - 4 = -4
\]
This point does not lie on the second equation.

2. For the point (0, -4):

- Substituting \( x = 0 \) in the first equation \( y = 2x + 2 \):
\[
y = 2(0) + 2 = 0 + 2 = 2
\]
This point does not lie on the first equation.

- Substituting \( x = 0 \) in the second equation \( y = 2x - 4 \):
\[
y = 2(0) - 4 = 0 - 4 = -4
\]
This point lies on the second equation.

Since (0, 2) satisfies the first equation but not the second, and (0, -4) satisfies the second equation but not the first, neither point is a solution to the system of equations.

Therefore, the correct response is:

**Neither of these points are solutions.**