32g of anhydrous copper(ii)tetraoxosulphate(iv) dissolves in 1Dm3 of water generated 13.0KJ of heat,The heat of solution is

Answer 1

My assumption is you mean CuSO4 but you have not named it correctly by IUPAC rules.
mols CuSO4 = grams/molar mass = 32/approx 159 = approx 0.2 but you need to recalculate ALL of these values. My numbers are just estimates.
dHsoln = kJ/mol = 13.0 kJ/0.2 mol = approx ?

Answer 2

Note: Since heat is generated dHsoln will be negative.