To find the pH of a 1 × 10⁻⁴ mol/L HCl solution, we need to consider that HCl is a strong acid and dissociates completely in water. Therefore, the concentration of hydrogen ions \([H^+]\) in the solution will be equal to the concentration of the acid.
- Given concentration of HCl = \(1 × 10^{-4} , \text{mol/L}\)
- \([H^+] = 1 × 10^{-4} , \text{mol/L}\)
The pH is calculated using the formula:
\[ pH = -\log[H^+] \]
Substituting the concentration:
\[ pH = -\log(1 × 10^{-4}) = -(-4) = 4 \]
Thus, the pH of a 1 × 10⁻⁴ mol/L HCl solution is 4.