To find the solution set for the inequalities \(4x - 3 > 9\) and \(x + 6 > -2\), we'll solve each inequality separately.
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Solve the first inequality: \[ 4x - 3 > 9 \] Add 3 to both sides: \[ 4x > 12 \] Now, divide both sides by 4: \[ x > 3 \]
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Solve the second inequality: \[ x + 6 > -2 \] Subtract 6 from both sides: \[ x > -8 \]
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Finding the intersection of the solution sets:
- The solution set for the first inequality is \(x > 3\).
- The solution set for the second inequality is \(x > -8\).
Now, we take the intersection of these two sets. Since \(x > 3\) is more restrictive than \(x > -8\), the solution to the combined inequalities is: \[ x > 3 \]
Thus, the solution set in set notation is: \[ { x \mid x > 3 } \]
So, the correct response is: \[ { x \mid x > 3 } \]