Question
What is the correct area formula for a trapezoid, A=1/2h(b1+b2), rearranged for the quantity of interest h?
Answers
GPT-4o mini
To rearrange the area formula for a trapezoid, \( A = \frac{1}{2} h (b_1 + b_2) \), to solve for \( h \), follow these steps:
1. Start with the original formula:
\[
A = \frac{1}{2} h (b_1 + b_2)
\]
2. Multiply both sides by 2 to eliminate the fraction:
\[
2A = h (b_1 + b_2)
\]
3. Now, divide both sides by \( (b_1 + b_2) \) to isolate \( h \):
\[
h = \frac{2A}{b_1 + b_2}
\]
Thus, the rearranged formula for \( h \) is:
\[
h = \frac{2A}{b_1 + b_2}
\]
1. Start with the original formula:
\[
A = \frac{1}{2} h (b_1 + b_2)
\]
2. Multiply both sides by 2 to eliminate the fraction:
\[
2A = h (b_1 + b_2)
\]
3. Now, divide both sides by \( (b_1 + b_2) \) to isolate \( h \):
\[
h = \frac{2A}{b_1 + b_2}
\]
Thus, the rearranged formula for \( h \) is:
\[
h = \frac{2A}{b_1 + b_2}
\]