To solve the problem, we can use the concept of inverse variation. The relationship can be expressed as:
\[ S \times W = k \]
where:
- \( S \) is the maximum speed,
- \( W \) is the weight of the freight,
- \( k \) is a constant.
From the information provided:
- For \( W = 30,025 \) pounds, \( S = 55 \) mph.
First, we calculate the constant \( k \):
\[ k = S \times W = 55 \times 30,025 \]
Calculating \( k \):
\[ k = 55 \times 30,025 = 1,648,375 \]
Next, we want to find the maximum speed \( S' \) when the weight \( W' \) is \( 35,250 \) pounds:
\[ S' \times 35,250 = 1,648,375 \]
Solving for \( S' \):
\[ S' = \frac{1,648,375}{35,250} \]
Now we calculate \( S' \):
\[ S' \approx 46.8 \]
Rounding to the nearest whole number gives us:
\[ S' \approx 47 \]
Thus, the maximum speed of the truck with 35,250 pounds of freight is about 47 miles per hour.