Asked by Edwin
A 24V battery of internal resistance of 10ohms is connected to a variable resistor. At what value of current drawn from battery the rate of heat produced by the resistor is maximum? Hence find its value.
Answers
Answered by
drwls
Delivered power is a maximum when the internal and external resistances are equal, as I recall. Therefore
Rexternal(optimum) = 10 ohms.
Current with that external resistance
= V/Rtotal = 24/20 = 1.2 Amps
Maximum power produced in external resistor =
I^2*Rexternal = (1.2)^2 * 10 = 14.40 W
Check: If I use Rexternal = 11 ohms instead, Rtotal = 21 ohms and I = (24/21) = 1.143 A
I^2 * Rext = 14.37 W
If you use Rexternal = 9 ohms, your will still get a power less than 14.4 W
Rexternal(optimum) = 10 ohms.
Current with that external resistance
= V/Rtotal = 24/20 = 1.2 Amps
Maximum power produced in external resistor =
I^2*Rexternal = (1.2)^2 * 10 = 14.40 W
Check: If I use Rexternal = 11 ohms instead, Rtotal = 21 ohms and I = (24/21) = 1.143 A
I^2 * Rext = 14.37 W
If you use Rexternal = 9 ohms, your will still get a power less than 14.4 W
Answered by
varsha
its not in options
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