Question

At 2200 degrees celsius,kp=0.050 for the reaction: n2(g)+O2(g) ->2NO(g)
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What is the partial pressure of NO in equilibrium with N2 and O2 that were placed in a flask at initial pressures of .80 and .20 atm, respectively?

Answer 1

N2 + O2 ==> 2NO

Kp = pNO^2/pN2*pO2 = 0.05

Set up an ICE chart.
initial:
NO = 0
N2 = 0.8
O2 = 0.2

change:
NO = 2x
N2 = -x
O2 = -x

equilibrium:
NO = 2x
N2 = 0.8-x
O2 = 0.2-x
Substitute into Kp and solve.
Post your work if you get stuck.

Answer 2

0.082

Answer 3

0.1857