Question
The booster club is selling refreshments. The following system of linear equations models the concession stand prices. Let represent the cost of a hot dog and represent the cost of the soda. Write the answers in decimal form. Solve the system of linear equations.
4h+4s=10
7h+5s=15
4h+4s=10
7h+5s=15
Answers
GPT-4o mini
To solve the system of equations, we have the following two equations:
1. \( 4h + 4s = 10 \)
2. \( 7h + 5s = 15 \)
We can simplify the first equation by dividing all terms by 4:
\[
h + s = 2.5 \quad (1)
\]
Next, we'll express \( s \) in terms of \( h \) from equation (1):
\[
s = 2.5 - h \quad (2)
\]
Now we'll substitute equation (2) into the second equation:
\[
7h + 5(2.5 - h) = 15
\]
This expands to:
\[
7h + 12.5 - 5h = 15
\]
Combining like terms gives:
\[
2h + 12.5 = 15
\]
Now, subtract 12.5 from both sides:
\[
2h = 15 - 12.5
\]
\[
2h = 2.5
\]
Dividing both sides by 2:
\[
h = 1.25
\]
Now, we can substitute \( h \) back into equation (2) to find \( s \):
\[
s = 2.5 - 1.25
\]
\[
s = 1.25
\]
Thus, the solution is:
\[
h = 1.25 \quad \text{(cost of a hot dog)}
\]
\[
s = 1.25 \quad \text{(cost of a soda)}
\]
So, the cost of both the hot dog and the soda is $1.25.
1. \( 4h + 4s = 10 \)
2. \( 7h + 5s = 15 \)
We can simplify the first equation by dividing all terms by 4:
\[
h + s = 2.5 \quad (1)
\]
Next, we'll express \( s \) in terms of \( h \) from equation (1):
\[
s = 2.5 - h \quad (2)
\]
Now we'll substitute equation (2) into the second equation:
\[
7h + 5(2.5 - h) = 15
\]
This expands to:
\[
7h + 12.5 - 5h = 15
\]
Combining like terms gives:
\[
2h + 12.5 = 15
\]
Now, subtract 12.5 from both sides:
\[
2h = 15 - 12.5
\]
\[
2h = 2.5
\]
Dividing both sides by 2:
\[
h = 1.25
\]
Now, we can substitute \( h \) back into equation (2) to find \( s \):
\[
s = 2.5 - 1.25
\]
\[
s = 1.25
\]
Thus, the solution is:
\[
h = 1.25 \quad \text{(cost of a hot dog)}
\]
\[
s = 1.25 \quad \text{(cost of a soda)}
\]
So, the cost of both the hot dog and the soda is $1.25.