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Real-World Systems of Equations Practice
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Question
The booster club is selling refreshments. The following system of linear equations models the concession stand prices. Let represent the cost of a hot dog and represent the cost of the soda. Write the answers in decimal form. Solve the system of linear equations.
4h+4s=10
7h+5s=15
(1 point)
h=$
s=$
Answers
Answered by
GPT-4o mini
To solve the system of linear equations given:
1. \( 4h + 4s = 10 \)
2. \( 7h + 5s = 15 \)
We can simplify the first equation by dividing everything by 4:
\[
h + s = 2.5 \quad \text{(Equation 1)}
\]
Now we rearrange Equation 1 to express \( s \) in terms of \( h \):
\[
s = 2.5 - h \quad \text{(Equation 3)}
\]
Next, we can substitute Equation 3 into the second equation (Equation 2):
\[
7h + 5(2.5 - h) = 15
\]
Distributing the 5 in the equation:
\[
7h + 12.5 - 5h = 15
\]
Now, combine like terms:
\[
2h + 12.5 = 15
\]
Subtract 12.5 from both sides:
\[
2h = 2.5
\]
Now divide by 2:
\[
h = 1.25
\]
Now that we have the value of \( h \), substitute it back into Equation 3 to find \( s \):
\[
s = 2.5 - h = 2.5 - 1.25 = 1.25
\]
Thus, the costs are:
\[
h = 1.25\, \text{and} \, s = 1.25
\]
In decimal form:
- \( h = \$1.25 \)
- \( s = \$1.25 \)
Final answers:
\[
h = 1.25 \quad s = 1.25
\]
1. \( 4h + 4s = 10 \)
2. \( 7h + 5s = 15 \)
We can simplify the first equation by dividing everything by 4:
\[
h + s = 2.5 \quad \text{(Equation 1)}
\]
Now we rearrange Equation 1 to express \( s \) in terms of \( h \):
\[
s = 2.5 - h \quad \text{(Equation 3)}
\]
Next, we can substitute Equation 3 into the second equation (Equation 2):
\[
7h + 5(2.5 - h) = 15
\]
Distributing the 5 in the equation:
\[
7h + 12.5 - 5h = 15
\]
Now, combine like terms:
\[
2h + 12.5 = 15
\]
Subtract 12.5 from both sides:
\[
2h = 2.5
\]
Now divide by 2:
\[
h = 1.25
\]
Now that we have the value of \( h \), substitute it back into Equation 3 to find \( s \):
\[
s = 2.5 - h = 2.5 - 1.25 = 1.25
\]
Thus, the costs are:
\[
h = 1.25\, \text{and} \, s = 1.25
\]
In decimal form:
- \( h = \$1.25 \)
- \( s = \$1.25 \)
Final answers:
\[
h = 1.25 \quad s = 1.25
\]
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