Question

2 and three-fifths minus 1 and one-fourth equals(1 point)
Responses


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Answer 1

To subtract the fractions \(2 \frac{3}{5} - 1 \frac{1}{4}\), we can follow these steps:

1. Convert the mixed numbers to improper fractions.
- \(2 \frac{3}{5} = \frac{2 \times 5 + 3}{5} = \frac{10 + 3}{5} = \frac{13}{5}\)
- \(1 \frac{1}{4} = \frac{1 \times 4 + 1}{4} = \frac{4 + 1}{4} = \frac{5}{4}\)

2. Subtract the improper fractions:
- To subtract the fractions, we need a common denominator. The least common multiple of 5 and 4 is 20.
- Convert \(\frac{13}{5}\) to have a denominator of 20:
\[
\frac{13}{5} = \frac{13 \times 4}{5 \times 4} = \frac{52}{20}
\]
- Convert \(\frac{5}{4}\) to have a denominator of 20:
\[
\frac{5}{4} = \frac{5 \times 5}{4 \times 5} = \frac{25}{20}
\]

3. Now, subtract the fractions:
\[
\frac{52}{20} - \frac{25}{20} = \frac{52 - 25}{20} = \frac{27}{20}
\]

4. Convert back to a mixed number:
- \(\frac{27}{20} = 1 \frac{7}{20}\) (since 27 divided by 20 gives 1 with a remainder of 7)

So, \(2 \frac{3}{5} - 1 \frac{1}{4} = 1 \frac{7}{20}\).

The final answer is \(1 \frac{7}{20}\).