To verify the claims made by Tamara, Payton, Krish, and Haruki, we need to solve each equation and check the solution sets.
**Equation A:**
\[ 3(4 - 5h) - 7 = -12 + 2h \]
Let's simplify:
\[ 3(4) - 3(5h) - 7 = -12 + 2h \]
\[ 12 - 15h - 7 = -12 + 2h \]
\[ 5 - 15h = -12 + 2h \]
Add \( 15h \) to both sides:
\[ 5 = -12 + 17h \]
Add 12 to both sides:
\[ 17 = 17h \]
Divide both sides by 17:
\[ h = 1 \]
So the solution for Equation A is \( h = 1 \).
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**Equation B:**
\[ 2(p - 3) - 1 = 6p + 142 \]
Let's simplify:
\[ 2p - 6 - 1 = 6p + 142 \]
\[ 2p - 7 = 6p + 142 \]
Subtract \( 2p \) from both sides:
\[ -7 = 4p + 142 \]
Subtract 142 from both sides:
\[ -149 = 4p \]
Divide both sides by 4:
\[ p = -\frac{149}{4} \]
So the solution for Equation B is \( p = -\frac{149}{4} \).
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**Equation C:**
\[ 23v - 3 + 83 = -1 \]
Let's simplify:
\[ 23v + 80 = -1 \]
Subtract 80 from both sides:
\[ 23v = -81 \]
Divide both sides by 23:
\[ v = -\frac{81}{23} \]
So the solution for Equation C is \( v = -\frac{81}{23} \).
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Now let's compare the solutions:
- **Equation A:** \( h = 1 \)
- **Equation B:** \( p = -\frac{149}{4} \)
- **Equation C:** \( v = -\frac{81}{23} \)
None of the equations have the same solutions. Therefore, Haruki is correct.
So the answer is: **Haruki**.