-10+1 67th term

1 answer

To find the 67th term of the arithmetic sequence starting from -10 with a common difference of 1, we can use the formula for the \( n \)-th term of an arithmetic sequence:

\[ a_n = a_1 + (n - 1) \cdot d \]

where:

  • \( a_n \) is the \( n \)-th term,
  • \( a_1 \) is the first term,
  • \( d \) is the common difference,
  • \( n \) is the term number.

In this case:

  • \( a_1 = -10 \)
  • \( d = 1 \)
  • \( n = 67 \)

Now substituting the values into the formula:

\[ a_{67} = -10 + (67 - 1) \cdot 1 \]

\[ a_{67} = -10 + 66 \]

\[ a_{67} = 56 \]

Therefore, the 67th term of the sequence is 56.