Question
Cruz wrote a system of equations with an infinite number of solutions. One of his equations is 6x+3y=9
. What could be his second equation? (Write the equation in slope-intercept form.)(1 point)
The second equation could be y=
. What could be his second equation? (Write the equation in slope-intercept form.)(1 point)
The second equation could be y=
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To create a second equation that has the same infinite solutions as the first equation \(6x + 3y = 9\), we need to ensure that the second equation is a multiple of the first equation.
First, we can simplify the first equation:
1. Divide the entire equation by 3:
\[
2x + y = 3
\]
2. Now, convert this equation to slope-intercept form \(y = mx + b\):
\[
y = -2x + 3
\]
Now, we can create a second equation by multiplying the entire equation by any non-zero constant \(k\). For example, let's choose \(k = 2\):
\[
2(2x + y) = 2(3)
\]
This leads to:
\[
4x + 2y = 6
\]
Now, we can convert it into slope-intercept form:
\[
2y = -4x + 6
\]
\[
y = -2x + 3
\]
We can choose any constant multiple. For instance, if \(k = 1/2\):
\[
\frac{1}{2}(6x + 3y) = \frac{1}{2}(9)
\]
This simplifies to:
\[
3x + \frac{3}{2}y = \frac{9}{2}
\]
Converting this equation to slope-intercept form gives:
\[
\frac{3}{2}y = -3x + \frac{9}{2}
\]
\[
y = -2x + 3
\]
Thus, one example for Cruz's second equation could be:
\[
y = -2x + 3
\]
Or he could choose any other multiple of the first equation, for example:
\[
y = -4x + 12
\]
So, a possible answer (which maintains an infinite number of solutions) could also be:
\[
y = -4x + 12
\]
You can express this as:
\[
y = -2x + 3
\]
as already mentioned, or in other equivalent forms.
First, we can simplify the first equation:
1. Divide the entire equation by 3:
\[
2x + y = 3
\]
2. Now, convert this equation to slope-intercept form \(y = mx + b\):
\[
y = -2x + 3
\]
Now, we can create a second equation by multiplying the entire equation by any non-zero constant \(k\). For example, let's choose \(k = 2\):
\[
2(2x + y) = 2(3)
\]
This leads to:
\[
4x + 2y = 6
\]
Now, we can convert it into slope-intercept form:
\[
2y = -4x + 6
\]
\[
y = -2x + 3
\]
We can choose any constant multiple. For instance, if \(k = 1/2\):
\[
\frac{1}{2}(6x + 3y) = \frac{1}{2}(9)
\]
This simplifies to:
\[
3x + \frac{3}{2}y = \frac{9}{2}
\]
Converting this equation to slope-intercept form gives:
\[
\frac{3}{2}y = -3x + \frac{9}{2}
\]
\[
y = -2x + 3
\]
Thus, one example for Cruz's second equation could be:
\[
y = -2x + 3
\]
Or he could choose any other multiple of the first equation, for example:
\[
y = -4x + 12
\]
So, a possible answer (which maintains an infinite number of solutions) could also be:
\[
y = -4x + 12
\]
You can express this as:
\[
y = -2x + 3
\]
as already mentioned, or in other equivalent forms.
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