Identify the pair of linear equations that have the same solution set.(1 point)

To determine which pair of linear equations have the same solution set, let's solve each pair of equations one by one.

1. **First pair:**
- \( 4k - 5 = 2k \)
- Rearranging, we get \( 4k - 2k = 5 \) → \( 2k = 5 \) → \( k = \frac{5}{2} \)

- \( 8j - 2 = 3j \)
- Rearranging, we get \( 8j - 3j = 2 \) → \( 5j = 2 \) → \( j = \frac{2}{5} \)

(Different solutions)

2. **Second pair:**
- \( 2(3g + 5) - 2g = 2(4 - g) \)
- Expanding: \( 6g + 10 - 2g = 8 - 2g \)
- Combining terms: \( 4g + 10 = 8 - 2g \) → \( 4g + 2g = 8 - 10 \) → \( 6g = -2 \) → \( g = -\frac{1}{3} \)

- \( -\frac{36h}{6} = 2 \) simplifies to \( -6h = 2 \) → \( h = -\frac{1}{3} \)

(Same solution)

3. **Third pair:**
- \( 4 = \frac{k}{2} + 5 \)
- Rearranging gives: \( \frac{k}{2} = 4 - 5 \) → \( \frac{k}{2} = -1 \) → \( k = -2 \)

- \( \frac{4j - 14}{3} + 5 = 3 \)
- Rearranging gives: \( \frac{4j - 14}{3} = 3 - 5 \) → \( \frac{4j - 14}{3} = -2 \) → \( 4j - 14 = -6 \) → \( 4j = 8 \) → \( j = 2 \)

(Different solutions)

4. **Fourth pair:**
- \( 3(m + 1) = 10 \)
- Expanding gives: \( 3m + 3 = 10 \) → \( 3m = 7 \) → \( m = \frac{7}{3} \)

- \( 6n + 3 = 6 - n \)
- Rearranging gives: \( 6n + n = 6 - 3 \) → \( 7n = 3 \) → \( n = \frac{3}{7} \)

(Different solutions)

After evaluating all pairs, the only pair with the same solution set is:

**2(3g + 5) - 2g = 2(4 - g) and −36h/6 = 2.**