Looking at the periodic table, determine the number of valence electrons present in a following neutral atoms.

Question

Column A
1.
Oxygen (O):
Oxygen (O)
2.
Aluminium (Al):
Aluminium (Al)
3.
Neon (Ne):
Neon (Ne)
4.
Silicion (Si):
Silicion (Si)
5.
Magnesium (Mg):
Magnesium (Mg)
6.
Iodine (I):
Iodine (I)
7.
Lithium (Li):
Lithium (Li)
8.
Nitrogen (N):
Nitrogen (N)
Column B
a.1 valence electrons
b.5 valence electrons
c.4 valence electrons
d.3 valence electrons
e.8 valence electrons
f.7 valence electrons
g.6 valence electrons
h.2 valence electrons

Answer 1

Here are the number of valence electrons for each of the listed neutral atoms and their corresponding options from Column B:

1. Oxygen (O): 6 valence electrons - g
2. Aluminium (Al): 3 valence electrons - d
3. Neon (Ne): 8 valence electrons - e
4. Silicon (Si): 4 valence electrons - c
5. Magnesium (Mg): 2 valence electrons - h
6. Iodine (I): 7 valence electrons - f
7. Lithium (Li): 1 valence electron - a
8. Nitrogen (N): 5 valence electrons - b

Here is the summary paired together:

1. O: g (6 valence electrons)
2. Al: d (3 valence electrons)
3. Ne: e (8 valence electrons)
4. Si: c (4 valence electrons)
5. Mg: h (2 valence electrons)
6. I: f (7 valence electrons)
7. Li: a (1 valence electron)
8. N: b (5 valence electrons)