Question
Ben is trying to determine if x = 2/3 is a solution to the quadratic equation 9x^2 + 3x − 5 = 6. Which explanation below demonstrates the correct reasoning?
A) No, x = 2/3 is not a solution because substituting it back into the equation results in 1 = 6, which is a false statement.
B) Yes, x = 2/3 is a solution because substituting it back into the equation results in 6 = 6, which is a true statement.
C) No, x = 2/3 is not a solution because substituting it back into the equation results in 6 = 6, which is a false statement.
D) Yes, x = 2/3 is a solution because substituting it back into the equation results in 1 = 6, which is a true statement.
A) No, x = 2/3 is not a solution because substituting it back into the equation results in 1 = 6, which is a false statement.
B) Yes, x = 2/3 is a solution because substituting it back into the equation results in 6 = 6, which is a true statement.
C) No, x = 2/3 is not a solution because substituting it back into the equation results in 6 = 6, which is a false statement.
D) Yes, x = 2/3 is a solution because substituting it back into the equation results in 1 = 6, which is a true statement.
Answers
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Answered by
GPT-4o mini
To determine if \( x = \frac{2}{3} \) is a solution to the equation \( 9x^2 + 3x - 5 = 6 \), we can substitute \( \frac{2}{3} \) into the left side of the equation and see if it equals 6.
1. Substitute \( x = \frac{2}{3} \) into the left side of the equation:
\[
9\left(\frac{2}{3}\right)^2 + 3\left(\frac{2}{3}\right) - 5
\]
2. Calculate \( 9\left(\frac{2}{3}\right)^2 \):
\[
\left(\frac{2}{3}\right)^2 = \frac{4}{9} \implies 9 \cdot \frac{4}{9} = 4
\]
3. Calculate \( 3\left(\frac{2}{3}\right) \):
\[
3 \cdot \frac{2}{3} = 2
\]
4. Combine these results:
\[
4 + 2 - 5 = 6 - 5 = 1
\]
5. The left side evaluates to 1, while the right side of the original equation is 6.
Since \( 1 \neq 6 \), we conclude that \( x = \frac{2}{3} \) is not a solution.
Thus, the correct explanation is:
**A)** No, \( x = \frac{2}{3} \) is not a solution because substituting it back into the equation results in \( 1 = 6 \), which is a false statement.
1. Substitute \( x = \frac{2}{3} \) into the left side of the equation:
\[
9\left(\frac{2}{3}\right)^2 + 3\left(\frac{2}{3}\right) - 5
\]
2. Calculate \( 9\left(\frac{2}{3}\right)^2 \):
\[
\left(\frac{2}{3}\right)^2 = \frac{4}{9} \implies 9 \cdot \frac{4}{9} = 4
\]
3. Calculate \( 3\left(\frac{2}{3}\right) \):
\[
3 \cdot \frac{2}{3} = 2
\]
4. Combine these results:
\[
4 + 2 - 5 = 6 - 5 = 1
\]
5. The left side evaluates to 1, while the right side of the original equation is 6.
Since \( 1 \neq 6 \), we conclude that \( x = \frac{2}{3} \) is not a solution.
Thus, the correct explanation is:
**A)** No, \( x = \frac{2}{3} \) is not a solution because substituting it back into the equation results in \( 1 = 6 \), which is a false statement.
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