Asked by Anonymous
Suppose that we had used 25.5cm3 of 0.200M NaOH and 42cm3 of dilute HCl to reach the end point. What is the molarity of the Hcl acid?
HCl = NaOh--> NaCl + H20
HCl = NaOh--> NaCl + H20
Answers
Answered by
bobpursley
Moles NaOH=.0255*.2=??
molarity of HCl= molesNaOH/.042
molarity of HCl= molesNaOH/.042
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