Asked by Lwalwa
A passage with a length of 8 m and breadth of 2 m
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Answered by
GPT-4o mini
It sounds like you're describing a rectangular passage with specific dimensions. If the passage has a length of 8 meters and a breadth of 2 meters, it can be visualized as a long and narrow area.
Here are a few characteristics based on these dimensions:
1. **Area**: The area of the passage can be calculated using the formula:
\[
\text{Area} = \text{Length} \times \text{Breadth} = 8 \, \text{m} \times 2 \, \text{m} = 16 \, \text{m}^2
\]
2. **Perimeter**: The perimeter is the distance around the passage and can be calculated as:
\[
\text{Perimeter} = 2 \times (\text{Length} + \text{Breadth}) = 2 \times (8 \, \text{m} + 2 \, \text{m}) = 2 \times 10 \, \text{m} = 20 \, \text{m}
\]
3. **Usage**: Such a passage could serve multiple purposes: it could be a walkway, a corridor between rooms, or even an access route in a building. The narrow width might suggest it’s designed for foot traffic rather than vehicle access.
If you need more specific information or context regarding this passage, feel free to share!
Here are a few characteristics based on these dimensions:
1. **Area**: The area of the passage can be calculated using the formula:
\[
\text{Area} = \text{Length} \times \text{Breadth} = 8 \, \text{m} \times 2 \, \text{m} = 16 \, \text{m}^2
\]
2. **Perimeter**: The perimeter is the distance around the passage and can be calculated as:
\[
\text{Perimeter} = 2 \times (\text{Length} + \text{Breadth}) = 2 \times (8 \, \text{m} + 2 \, \text{m}) = 2 \times 10 \, \text{m} = 20 \, \text{m}
\]
3. **Usage**: Such a passage could serve multiple purposes: it could be a walkway, a corridor between rooms, or even an access route in a building. The narrow width might suggest it’s designed for foot traffic rather than vehicle access.
If you need more specific information or context regarding this passage, feel free to share!
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