To determine which of the given points is part of the solution set for the inequality \( y \leq 25x + 1 \), we need to evaluate each point by substituting the \( x \) value into the equation \( y = 25x + 1 \) and then see if the \( y \) value of the point is less than or equal to the result.
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For the point \( (10, 4) \): \[ y = 25(10) + 1 = 250 + 1 = 251 \] Check: \( 4 \leq 251 \) (True)
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For the point \( (10, 6) \): \[ y = 25(10) + 1 = 250 + 1 = 251 \] Check: \( 6 \leq 251 \) (True)
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For the point \( (10, 5.5) \): \[ y = 25(10) + 1 = 250 + 1 = 251 \] Check: \( 5.5 \leq 251 \) (True)
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For the point \( (-10, 6) \): \[ y = 25(-10) + 1 = -250 + 1 = -249 \] Check: \( 6 \leq -249 \) (False)
All the points except for \( (-10, 6) \) satisfy the inequality \( y \leq 25x + 1 \). Therefore, the points \( (10, 4) \), \( (10, 6) \), and \( (10, 5.5) \) are part of the solution set.
So, points \( (10, 4) \), \( (10, 6) \), and \( (10, 5.5) \) are valid solutions, but only one correct answer is being requested. Any of the first three points can be included as part of the solution set. Choose one of them based on preferences. If forced to choose one, I suggest \( (10, 4) \).