Question

determine the number of valence electrons present in a following neutral atoms.

Column A
1.
Oxygen (O):
Oxygen (O)
2.
Aluminium (Al):
Aluminium (Al)
3.
Neon (Ne):
Neon (Ne)
4.
Silicion (Si):
Silicion (Si)
5.
Magnesium (Mg):
Magnesium (Mg)
6.
Iodine (I):
Iodine (I)
7.
Lithium (Li):
Lithium (Li)
8.
Nitrogen (N):
Nitrogen (N)
Column B
a.3 valence electrons
b.2 valence electrons
c.7 valence electrons
d.1 valence electrons
e.5 valence electrons
f.8 valence electrons
g.4 valence electrons
h.6 valence electrons

Answer 1

Here are the number of valence electrons for each of the neutral atoms listed in Column A, along with their corresponding options from Column B:

1. **Oxygen (O)**: 6 valence electrons (h)
2. **Aluminium (Al)**: 3 valence electrons (a)
3. **Neon (Ne)**: 8 valence electrons (f)
4. **Silicon (Si)**: 4 valence electrons (g)
5. **Magnesium (Mg)**: 2 valence electrons (b)
6. **Iodine (I)**: 7 valence electrons (c)
7. **Lithium (Li)**: 1 valence electron (d)
8. **Nitrogen (N)**: 5 valence electrons (e)

Here they are matched correctly:

- Oxygen (O): 6 valence electrons (h)
- Aluminium (Al): 3 valence electrons (a)
- Neon (Ne): 8 valence electrons (f)
- Silicon (Si): 4 valence electrons (g)
- Magnesium (Mg): 2 valence electrons (b)
- Iodine (I): 7 valence electrons (c)
- Lithium (Li): 1 valence electron (d)
- Nitrogen (N): 5 valence electrons (e)