Asked by Zoey

Find derivative(use logrithmic functions).
y=x^-cosx

Answers

Answered by Damon
y=x^-cosx
ln y = -cos x ln x

d/dx( ln y ) = d/dx (-cos x lnx)

(1/y)dy/dx = (-cos x) / x + ln x sin x

dy/dx = [ln x sin x - (1/x) cos x] /y

= [ln x sin x - (1/x) cos x] x^cos x

Answered by Damon
dy/dx = [ln x sin x - (1/x) cos x] y

= [ln x sin x - (1/x) cos x] x^cos-x
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