Asked by keisha
refer to a bag of marbles containing 5 green marbles, 4 red marbles and 2 yellow marbles. Three marbles are drawn from the bag, without replacement. What is the probabilty that all three marbles drawn are green?
Answers
Answered by
Damon
11 marbles, 5 green
probability that #1 is green = 5/11
now 10 marbles, 4 green
probability that #2 is green = 4/10
now 9 marbles, 3 green
probability that #3 is green = 3/9
so
5/11 * 2/5 * 1/3
= 2/33
probability that #1 is green = 5/11
now 10 marbles, 4 green
probability that #2 is green = 4/10
now 9 marbles, 3 green
probability that #3 is green = 3/9
so
5/11 * 2/5 * 1/3
= 2/33
Answered by
keisha
thanks what is the probability that at least one of the marbles drawn is green? I thinks it's 1/11 but not sure.
Then what is the probability that only one of the marbles drawn are green?
Then what is the probability that only one of the marbles drawn are green?