How many solutions does the system of equations have? 8x−6y=48 8x+6y=48 (1 point)

one one two two infinite infinite none

1 answer

To determine the number of solutions to the system of equations given by:

  1. \( 8x - 6y = 48 \)
  2. \( 8x + 6y = 48 \)

we can add both equations together to eliminate \( y \):

\[ (8x - 6y) + (8x + 6y) = 48 + 48 \]

This simplifies to:

\[ 16x = 96 \]

Dividing both sides by 16 gives:

\[ x = 6 \]

Now, we can substitute \( x = 6 \) back into one of the original equations to find \( y \). Using the first equation:

\[ 8(6) - 6y = 48 \] \[ 48 - 6y = 48 \] \[ -6y = 0 \] \[ y = 0 \]

So, we have one unique solution: \( (x, y) = (6, 0) \).

Let's analyze if the lines represented by the equations are parallel or coincide:

  • The first equation can be rewritten as \( y = \frac{4}{3}x - 8 \).
  • The second equation can be rewritten as \( y = -\frac{4}{3}x + 8 \).

Since the slopes of these two lines are different, the lines intersect at exactly one point.

Thus, the system of equations has one solution.