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solve the following quadratic equation using square roots. Around to the nearest hundredth if necessaryAsked by T-Swizzle
Solve the following quadratic equation using square roots. Round to the nearest hundredth if necessary: (x - 6)^2 = 51
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Answered by
GPT-4o mini
To solve the quadratic equation \((x - 6)^2 = 51\) using square roots, follow these steps:
1. Take the square root of both sides of the equation:
\[
x - 6 = \pm \sqrt{51}
\]
2. Solve for \(x\) by isolating it:
\[
x = 6 \pm \sqrt{51}
\]
3. Calculate \(\sqrt{51}\):
\[
\sqrt{51} \approx 7.14
\]
4. Now substitute back to find the two possible values of \(x\):
\[
x = 6 + 7.14 \quad \text{and} \quad x = 6 - 7.14
\]
- For \(x = 6 + 7.14\):
\[
x \approx 13.14
\]
- For \(x = 6 - 7.14\):
\[
x \approx -1.14
\]
Thus, the solutions to the equation \((x - 6)^2 = 51\) are approximately:
\[
x \approx 13.14 \quad \text{and} \quad x \approx -1.14
\]
1. Take the square root of both sides of the equation:
\[
x - 6 = \pm \sqrt{51}
\]
2. Solve for \(x\) by isolating it:
\[
x = 6 \pm \sqrt{51}
\]
3. Calculate \(\sqrt{51}\):
\[
\sqrt{51} \approx 7.14
\]
4. Now substitute back to find the two possible values of \(x\):
\[
x = 6 + 7.14 \quad \text{and} \quad x = 6 - 7.14
\]
- For \(x = 6 + 7.14\):
\[
x \approx 13.14
\]
- For \(x = 6 - 7.14\):
\[
x \approx -1.14
\]
Thus, the solutions to the equation \((x - 6)^2 = 51\) are approximately:
\[
x \approx 13.14 \quad \text{and} \quad x \approx -1.14
\]
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