Asked by Jamal
For the following reaction, 0.506 moles of ammonia are mixed with 0.458 moles
of oxygen gas.
ammonia (g) + oxygen (g) nitrogen monoxide (g) + water (g)
What is the FORMULA for the limiting reagent?
What is the maximum amount of nitrogen monoxide that can be produced? moles
of oxygen gas.
ammonia (g) + oxygen (g) nitrogen monoxide (g) + water (g)
What is the FORMULA for the limiting reagent?
What is the maximum amount of nitrogen monoxide that can be produced? moles
Answers
Answered by
bobpursley
Balance the equation. Determine from the coefficents the mole ratio.
Given .506moles of NH3, how many moles of O2 do you need? Do you have that much, or more? If you do not have that much, then O2 is limiting, otherwise, you have an excess of O2 and NH3 is limiting.
I will be happy to critique your work.
Given .506moles of NH3, how many moles of O2 do you need? Do you have that much, or more? If you do not have that much, then O2 is limiting, otherwise, you have an excess of O2 and NH3 is limiting.
I will be happy to critique your work.
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