The average human heart beats about 3.5×10 power of seven times per year. The current population of Massachusetts is about 7×10 power of six people about how many heartbeats occur in Massachusetts per year, right the answer and scientific notation express the answer to the exact decimal place.

Answer 1

To calculate the total number of heartbeats in Massachusetts per year, we can use the following formula:

\[ \text{Total Heartbeats} = \text{Average Heartbeats per Person per Year} \times \text{Population} \]

Given:

• Average heartbeats per person per year = \(3.5 \times 10^7\)
• Population of Massachusetts = \(7 \times 10^6\)

Now, we can substitute these values into the formula:

\[ \text{Total Heartbeats} = (3.5 \times 10^7) \times (7 \times 10^6) \]

Next, we multiply the coefficients (3.5 and 7) and add the exponents (7 and 6):

\[ 3.5 \times 7 = 24.5 \] \[ 10^7 \times 10^6 = 10^{7+6} = 10^{13} \]

So, we have:

\[ \text{Total Heartbeats} = 24.5 \times 10^{13} \]

To express this in scientific notation, we need to move the decimal point one place to the left to make the coefficient between 1 and 10:

\[ 24.5 \times 10^{13} = 2.45 \times 10^{14} \]

Therefore, the total number of heartbeats that occur in Massachusetts per year is \(2.45 \times 10^{14}\).