Question
expand and simplify (x+3)(x-3)(3x+2)
Answers
Answered by
GPT-4o mini
To expand and simplify the expression \((x + 3)(x - 3)(3x + 2)\), we can follow these steps:
1. **Recognize the difference of squares**: The expression \((x + 3)(x - 3)\) can be simplified first because it represents a difference of squares.
\[
(x + 3)(x - 3) = x^2 - 9
\]
2. **Substitute the result into the third factor**: Now we replace \((x + 3)(x - 3)\) with \(x^2 - 9\):
\[
(x^2 - 9)(3x + 2)
\]
3. **Distribute \((3x + 2)\) over \((x^2 - 9)\)**:
\[
(x^2 - 9)(3x + 2) = x^2(3x + 2) - 9(3x + 2)
\]
Now, distributing each term:
\[
x^2(3x + 2) = 3x^3 + 2x^2
\]
\[
-9(3x + 2) = -27x - 18
\]
4. **Combine all the terms**:
\[
3x^3 + 2x^2 - 27x - 18
\]
Now, the expanded and simplified form of \((x + 3)(x - 3)(3x + 2)\) is:
\[
\boxed{3x^3 + 2x^2 - 27x - 18}
\]
1. **Recognize the difference of squares**: The expression \((x + 3)(x - 3)\) can be simplified first because it represents a difference of squares.
\[
(x + 3)(x - 3) = x^2 - 9
\]
2. **Substitute the result into the third factor**: Now we replace \((x + 3)(x - 3)\) with \(x^2 - 9\):
\[
(x^2 - 9)(3x + 2)
\]
3. **Distribute \((3x + 2)\) over \((x^2 - 9)\)**:
\[
(x^2 - 9)(3x + 2) = x^2(3x + 2) - 9(3x + 2)
\]
Now, distributing each term:
\[
x^2(3x + 2) = 3x^3 + 2x^2
\]
\[
-9(3x + 2) = -27x - 18
\]
4. **Combine all the terms**:
\[
3x^3 + 2x^2 - 27x - 18
\]
Now, the expanded and simplified form of \((x + 3)(x - 3)(3x + 2)\) is:
\[
\boxed{3x^3 + 2x^2 - 27x - 18}
\]