To determine which points would appear on the linear function \( C = 1.25m + 25 \), we can substitute the values of \( m \) (miles driven) from each pair of options into the equation and see if we get the corresponding value for \( C \) (total cost).
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For (2, 2.5):
- \( m = 2 \)
- \( C = 1.25(2) + 25 = 2.5 + 25 = 27.5 \) (not (2, 2.5))
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For (4, 22.5):
- \( m = 4 \)
- \( C = 1.25(4) + 25 = 5 + 25 = 30 \) (not (4, 22.5))
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For (30, 4):
- \( m = 30 \)
- \( C = 1.25(30) + 25 = 37.5 + 25 = 62.5 \) (not (30, 4))
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For (35, 8):
- \( m = 35 \)
- \( C = 1.25(35) + 25 = 43.75 + 25 = 68.75 \) (not (35, 8))
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For (4, 30):
- \( m = 4 \)
- \( C = 1.25(4) + 25 = 5 + 25 = 30 \) (this is correct)
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For (8, 35):
- \( m = 8 \)
- \( C = 1.25(8) + 25 = 10 + 25 = 35 \) (this is also correct)
Thus, the points (4, 30) and (8, 35) satisfy the equation \( C = 1.25m + 25 \). Therefore, the correct response is:
(4, 30) and (8, 35)