Question

Solve the following quadratic equation using square roots: (x+3)^2=36
.(1 point)
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Answer 1

To solve the quadratic equation \((x + 3)^2 = 36\) using square roots, we start by taking the square root of both sides:

\[
x + 3 = \pm 6
\]

This gives us two equations to solve:

1. \(x + 3 = 6\)
2. \(x + 3 = -6\)

Now we solve each equation individually.

**For the first equation:**
\[
x + 3 = 6
\]
Subtract 3 from both sides:
\[
x = 6 - 3
\]
\[
x = 3
\]

**For the second equation:**
\[
x + 3 = -6
\]
Subtract 3 from both sides:
\[
x = -6 - 3
\]
\[
x = -9
\]

Thus, the solutions to the equation \((x + 3)^2 = 36\) are:
\[
x = 3 \quad \text{and} \quad x = -9
\]