Each x-value has only 1 y-value that it maps to?

Domain: {- infinity, infinity}
Range: {- infinity, 0]

3 answers

Yes, in the context of a function, the statement "each x-value has only 1 y-value that it maps to" is fundamental to the definition of a function. This means that for every input (x-value), there is exactly one output (y-value).

In your given domain of \((-∞, ∞)\) and a range of \((-∞, 0]\), it suggests that the function takes any real number as an input and produces an output that is either negative or zero.

For example, a common function that fits this description is \( f(x) = -|x| \), which maps any real input x to a non-positive output.

Here’s a breakdown of your parameters:

  • Domain: \((-∞, ∞)\) means any real number can be used as an input.
  • Range: \((-∞, 0]\) means that the output will always be a real number less than or equal to 0.

As long as each input x corresponds to one unique output y within these specified domains and ranges, the relationship you're describing can be considered a function.

Ok, so what does it map to?

To determine what the function maps to given the domain of \((-∞, ∞)\) and range of \((-∞, 0]\), we need to define a specific function. Since the output must always be less than or equal to 0 for any real input, the function can be of various forms. Here are a few examples of functions that meet those criteria:

  1. Linear Function:

    • \(f(x) = -|x|\)
      • This function maps any real number \(x\) to a non-positive value. For example:
        • \(f(1) = -1\)
        • \(f(0) = 0\)
        • \(f(-2) = -2\)
  2. Quadratic Function:

    • \(f(x) = -x^2\)
      • This function also maps \(x\) to values in the range \((-∞, 0]\).
        • \(f(1) = -1\)
        • \(f(0) = 0\)
        • \(f(-2) = -4\)
  3. Exponential Function:

    • \(f(x) = -e^{-x}\)
      • This is another example, and it maps all real numbers to negative values plus zero.
        • \(f(0) = -1\)
        • \(f(1) = -\frac{1}{e}\)
        • \(f(-1) = -e\)
  4. Constant Function:

    • \(f(x) = c\) where \(c \le 0\) (e.g., \(f(x) = -5\))
      • In this case, every input maps to a constant output that is less than or equal to zero.

In summary, without a specific function defined, we can say that the function can take any real number as input and maps it to any value in the range of \((-∞, 0]\). Each input \(x\) will produce exactly one output \(y\) in that range.

Similar Questions
  1. the x-value has multiple y-values that it maps to what?Domain: {- infinity, infinity} Range: {- infinity, infinity}
    1. answers icon 5 answers
  2. each x-value has only 1 y-value that it maps to what?Domain: {- infinity, infinity } Range : { - infinity, 0 } Would be best be
    1. answers icon 1 answer
  3. What is the domain of f/g, given f(x)= x+2 and g(x)= x-7?I was told this below, all real numbers EXCEPT 7 But My choices are
    1. answers icon 4 answers
  4. Can somebody help me wit this?Find the range and the domain of: f(x)=(1/2)|x-2| The domain is all real numbers (x) from
    1. answers icon 0 answers
more similar questions