Question
Place the numbers in descending order.
2.3 × 10−10
; 3.2 × 10−10
; 2.3 × 10−12
; 2.3 × 10−8 theres only 4 boxes
2.3 × 10−10
; 3.2 × 10−10
; 2.3 × 10−12
; 2.3 × 10−8 theres only 4 boxes
Answers
GPT-4o mini
To place the numbers in descending order, we can first compare the exponents and then the coefficients.
The numbers are:
1. \( 2.3 \times 10^{-10} \)
2. \( 3.2 \times 10^{-10} \)
3. \( 2.3 \times 10^{-12} \)
4. \( 2.3 \times 10^{-8} \)
Now, let's compare them based on their powers of 10:
1. \( 2.3 \times 10^{-8} \) (highest exponent)
2. \( 3.2 \times 10^{-10} \) (next highest exponent)
3. \( 2.3 \times 10^{-10} \)
4. \( 2.3 \times 10^{-12} \) (lowest exponent)
Now, putting them in descending order:
1. \( 2.3 \times 10^{-8} \)
2. \( 3.2 \times 10^{-10} \)
3. \( 2.3 \times 10^{-10} \)
4. \( 2.3 \times 10^{-12} \)
So the final order is:
**2.3 × 10−8, 3.2 × 10−10, 2.3 × 10−10, 2.3 × 10−12**.
The numbers are:
1. \( 2.3 \times 10^{-10} \)
2. \( 3.2 \times 10^{-10} \)
3. \( 2.3 \times 10^{-12} \)
4. \( 2.3 \times 10^{-8} \)
Now, let's compare them based on their powers of 10:
1. \( 2.3 \times 10^{-8} \) (highest exponent)
2. \( 3.2 \times 10^{-10} \) (next highest exponent)
3. \( 2.3 \times 10^{-10} \)
4. \( 2.3 \times 10^{-12} \) (lowest exponent)
Now, putting them in descending order:
1. \( 2.3 \times 10^{-8} \)
2. \( 3.2 \times 10^{-10} \)
3. \( 2.3 \times 10^{-10} \)
4. \( 2.3 \times 10^{-12} \)
So the final order is:
**2.3 × 10−8, 3.2 × 10−10, 2.3 × 10−10, 2.3 × 10−12**.