To solve the expression \( 6 - 4(3 - 1)^2 + 16 \), we follow the order of operations (parentheses, exponents, multiplication and division from left to right, addition and subtraction from left to right).
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Start with the parentheses: \[ 3 - 1 = 2 \]
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Now substitute back into the expression: \[ 6 - 4(2)^2 + 16 \]
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Next, calculate the exponent: \[ (2)^2 = 4 \]
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Substitute this back into the expression: \[ 6 - 4(4) + 16 \]
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Now perform the multiplication: \[ 4(4) = 16 \]
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Substitute this back into the expression: \[ 6 - 16 + 16 \]
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Now perform the addition and subtraction from left to right: \[ 6 - 16 = -10 \] \[ -10 + 16 = 6 \]
Thus, the final result is: \[ \boxed{6} \]