Question

The velocity of sound on a particular day outside is 331 meters/second. What is the frequency of a tone if it has a wavelength of 0.6 meters?
A.
5.52 × 102 hertz
B.
2.56 × 102 hertz
C.
459 × 102 hertz
D.
675 × 102 hertz
E.
990 × 102 hertz

Answer 1

To find the frequency of a tone, you can use the equation:

$$
\text{Frequency} (f) = \frac{\text{Velocity} (v)}{\text{Wavelength} (\lambda)}
$$

where:
- \( v \) is the velocity of sound (331 m/s),
- \( \lambda \) is the wavelength (0.6 m).

Now, plug in the values:

\[
f = \frac{331 \, \text{m/s}}{0.6 \, \text{m}} \approx 551.67 \, \text{Hz}
\]

To express this in scientific notation:

\[
f \approx 5.52 \times 10^2 \, \text{Hz}
\]

So the answer is:

**A. 5.52 × 10² hertz**