To find a line that is parallel to the line given by the equation \( y = \frac{5}{6}x \) and also passes through the point \( (12, 6) \), we need to maintain the same slope, which is \( \frac{5}{6} \).
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Since the slope of the new line will also be \( \frac{5}{6} \), we can use the point-slope form of a line, which is \( y - y_1 = m(x - x_1) \), where \( (x_1, y_1) \) is the point the line goes through, and \( m \) is the slope.
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Plugging in the point \( (12, 6) \) and the slope \( \frac{5}{6} \):
\[ y - 6 = \frac{5}{6}(x - 12) \]
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Distributing the slope:
\[ y - 6 = \frac{5}{6}x - 10 \]
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Adding 6 to both sides:
\[ y = \frac{5}{6}x - 4 \]
Now let's look at the given responses:
- \( 6y = 5x \)
- \( y = \frac{5}{6}x + 6 \)
- \( y = -\frac{6}{5}x + 6 \)
- \( y = \frac{5}{6}x - 4 \)
The equation we derived, \( y = \frac{5}{6}x - 4 \), matches exactly with the fourth option.
Thus, the correct response is:
\( y = \frac{5}{6}x - 4 \).