To determine which of the given lines is parallel to \( y = \frac{3}{4}x - 2 \), we need to find lines with the same slope. The slope of the given line is \( \frac{3}{4} \).
Let's analyze the slopes of the lines given in standard form:
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For the line \( 4x - 3y = 6 \):
- Rearranging to slope-intercept form ( \( y = mx + b \)): \[ -3y = -4x + 6 \ y = \frac{4}{3}x - 2 \]
- Slope: \( \frac{4}{3} \) (not parallel)
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For the line \( 3x - 4y = 12 \):
- Rearranging: \[ -4y = -3x + 12 \ y = \frac{3}{4}x - 3 \]
- Slope: \( \frac{3}{4} \) (parallel)
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For the line \( 4x - 3y = 12 \):
- Rearranging: \[ -3y = -4x + 12 \ y = \frac{4}{3}x - 4 \]
- Slope: \( \frac{4}{3} \) (not parallel)
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For the line \( 3x - 4y = 8 \):
- Rearranging: \[ -4y = -3x + 8 \ y = \frac{3}{4}x - 2 \]
- Slope: \( \frac{3}{4} \) (parallel)
The lines \( 3x - 4y = 12 \) and \( 3x - 4y = 8 \) are both parallel to \( y = \frac{3}{4}x - 2 \).
Thus, the correct answers are \( 3x - 4y = 12 \) and \( 3x - 4y = 8 \).