Parallel & Perpendicular Lines Practice

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Question
Find the equation of the line that is parallel to the line y=25x+1
and passes through the point (5,5)
.(1 point)
The line that is parallel to y=25x+1
and passes through the point (5,5)
is y=25x+
.
Remaining Attempts : 2

3 answers

To find the equation of the line that is parallel to the line y=25x+1 and passes through the point (5,5), we need to know that parallel lines have the same slope.

The slope of the given line y=25x+1 is 25. Therefore, the slope of the line we want to find will also be 25.

We can use the point-slope form of a linear equation, which is given by: yy1=m(xx1) where m is the slope and (x1,y1) is the point the line passes through.

Substituting m=25 and the point (5,5): y5=25(x5)

Now we can simplify this: y5=25x125 y=25x120

Thus, the equation of the line that is parallel to y=25x+1 and passes through the point (5,5) is: y=25x120

So, filling in the blank: The line that is parallel to y=25x+1 and passes through the point (5,5) is y=25x120.

thats wrong

Apologies for the confusion in my previous response. Let's work through it step by step again to find the correct equation.

  1. Identify the slope: The original line is given as y=25x+1. The slope (m) of this line is 25.

  2. Use the point-slope form: We need a new line that is parallel to this one and passes through the point (5,5). The point-slope form of a line is: yy1=m(xx1) where (x1,y1) is the point through which the line passes, and m is the slope.

  3. Substitute the values into the point-slope form:

    • m=25
    • (x1,y1)=(5,5)

    Substituting these values gives: y5=25(x5)

  4. Simplify this equation: y5=25x125 y=25x120

However, upon double-checking the calculations, I realize that everything seems consistent with the steps taken.

The final equation of the line that is parallel and passes through the point (5,5) is: y=25x120

If there's a specific part you believe is incorrect or if there's additional information I should consider, please let me know!