Question
using long division determine which of the following polynomials divides evenlt forna diviser of x+3
A. 4x^3+ 13
B. 6x^7+ -7
C. 12x^9+13
D. 6x^7+ 4x^3
A. 4x^3+ 13
B. 6x^7+ -7
C. 12x^9+13
D. 6x^7+ 4x^3
Answers
Answer
What is the correct answer
Answered by
GPT-4o mini
To determine which of the given polynomials is divisible by the polynomial \( x + 3 \), we can use the Remainder Theorem. According to this theorem, a polynomial \( f(x) \) is divisible by \( x + c \) if and only if \( f(-c) = 0 \). In this case, we have \( c = 3 \), so we will evaluate each polynomial at \( x = -3 \).
Let's evaluate each polynomial one by one:
**A. \( 4x^3 + 13 \)**
\[
f(-3) = 4(-3)^3 + 13 = 4(-27) + 13 = -108 + 13 = -95 \quad (\text{Not divisible})
\]
**B. \( 6x^7 - 7 \)**
\[
f(-3) = 6(-3)^7 - 7 = 6(-2187) - 7 = -13122 - 7 = -13129 \quad (\text{Not divisible})
\]
**C. \( 12x^9 + 13 \)**
\[
f(-3) = 12(-3)^9 + 13 = 12(-19683) + 13 = -236196 + 13 = -236183 \quad (\text{Not divisible})
\]
**D. \( 6x^7 + 4x^3 \)**
\[
f(-3) = 6(-3)^7 + 4(-3)^3 = 6(-2187) + 4(-27) = -13122 - 108 = -13230 \quad (\text{Not divisible})
\]
After evaluating all the polynomials at \( x = -3 \), none of them resulted in \( 0 \). Thus, none of the polynomials listed (A, B, C, or D) are divisible by \( x + 3 \).
Let's evaluate each polynomial one by one:
**A. \( 4x^3 + 13 \)**
\[
f(-3) = 4(-3)^3 + 13 = 4(-27) + 13 = -108 + 13 = -95 \quad (\text{Not divisible})
\]
**B. \( 6x^7 - 7 \)**
\[
f(-3) = 6(-3)^7 - 7 = 6(-2187) - 7 = -13122 - 7 = -13129 \quad (\text{Not divisible})
\]
**C. \( 12x^9 + 13 \)**
\[
f(-3) = 12(-3)^9 + 13 = 12(-19683) + 13 = -236196 + 13 = -236183 \quad (\text{Not divisible})
\]
**D. \( 6x^7 + 4x^3 \)**
\[
f(-3) = 6(-3)^7 + 4(-3)^3 = 6(-2187) + 4(-27) = -13122 - 108 = -13230 \quad (\text{Not divisible})
\]
After evaluating all the polynomials at \( x = -3 \), none of them resulted in \( 0 \). Thus, none of the polynomials listed (A, B, C, or D) are divisible by \( x + 3 \).
Answered by
GPT-4o mini
To find out which polynomial is divisible by \( x + 3 \), let's evaluate the polynomials more carefully using polynomial long division. However, since none of the previous evaluations provided a result of zero when substituting \( x = -3 \), I can confirm that none of them are divisible by \( x + 3 \) based on the Remainder Theorem.
### Rechecking with the Remainder Theorem:
1. **A**: \( 4x^3 + 13 \)
- \( f(-3) = 4(-3)^3 + 13 = 4(-27) + 13 = -108 + 13 = -95 \) (not divisible)
2. **B**: \( 6x^7 - 7 \)
- \( f(-3) = 6(-3)^7 - 7 = 6(-2187) - 7 = -13122 - 7 = -13129 \) (not divisible)
3. **C**: \( 12x^9 + 13 \)
- \( f(-3) = 12(-3)^9 + 13 = 12(-19683) + 13 = -236196 + 13 = -236183 \) (not divisible)
4. **D**: \( 6x^7 + 4x^3 \)
- \( f(-3) = 6(-3)^7 + 4(-3)^3 = 6(-2187) + 4(-27) = -13122 - 108 = -13230 \) (not divisible)
### Conclusion
After performing the evaluations correctly, I can confirm once again that none of the polynomials are divisible by \( x + 3 \). Thus, the answer is that there is **no correct answer** among the provided options, as all yield non-zero remainders when evaluated at \( x = -3 \).
If you meant a different polynomial or a different divisor, please clarify, and I'll be happy to assist!
### Rechecking with the Remainder Theorem:
1. **A**: \( 4x^3 + 13 \)
- \( f(-3) = 4(-3)^3 + 13 = 4(-27) + 13 = -108 + 13 = -95 \) (not divisible)
2. **B**: \( 6x^7 - 7 \)
- \( f(-3) = 6(-3)^7 - 7 = 6(-2187) - 7 = -13122 - 7 = -13129 \) (not divisible)
3. **C**: \( 12x^9 + 13 \)
- \( f(-3) = 12(-3)^9 + 13 = 12(-19683) + 13 = -236196 + 13 = -236183 \) (not divisible)
4. **D**: \( 6x^7 + 4x^3 \)
- \( f(-3) = 6(-3)^7 + 4(-3)^3 = 6(-2187) + 4(-27) = -13122 - 108 = -13230 \) (not divisible)
### Conclusion
After performing the evaluations correctly, I can confirm once again that none of the polynomials are divisible by \( x + 3 \). Thus, the answer is that there is **no correct answer** among the provided options, as all yield non-zero remainders when evaluated at \( x = -3 \).
If you meant a different polynomial or a different divisor, please clarify, and I'll be happy to assist!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.