Asked by Alan
Copper(I) Iodide is synthesised by the equation:
2CuSO4.5H2O + 2KI + 2Na2S2O3.5H2O --> 2CuI + K2SO4 + Na2SO4 + Na2S4O6 + 10H2O
Would it make a difference if anhydrous CuSO4 and Na2S2O3 are used instead? Why hydrous CuSO4 and Na2S2O3 are used instead?
2CuSO4.5H2O + 2KI + 2Na2S2O3.5H2O --> 2CuI + K2SO4 + Na2SO4 + Na2S4O6 + 10H2O
Would it make a difference if anhydrous CuSO4 and Na2S2O3 are used instead? Why hydrous CuSO4 and Na2S2O3 are used instead?
Answers
Answered by
DrBob222
I'm sure the primary reason is that is the way CuSO4 and Na2S2O3 come. I'm also sure that if the anhydrous material is placed in water they will pick up water of hydration. I know for a fact that CuSO4 will and I'm relatively sure Na2S2O3 will do the same.
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