To solve your question, we need to understand the relationship between the two squares and the triangle described.
The triangle is drawn within the squares, and since we have two squares with areas, we can derive their side lengths and understand how these relate to a right triangle.
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Square A: If square A has an area of \( A_a \) (it seems there's a typo in your message with "squared square"), then we can express its side length \( s_a \) as follows: \[ s_a = \sqrt{A_a} \] Since the area of square A is not stated, we leave it as \( A_a \).
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Square B: We have an area of square B as 45 units squared, so: \[ A_b = 45 \] The side length \( s_b \) of square B is: \[ s_b = \sqrt{45} = 3\sqrt{5} \]
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Square C: We need to find the area of square C, which must form a right triangle with the sides of squares A and B. Assuming square C also has an area \( A_c \), according to the Pythagorean theorem in the context of the squares we have: \[ A_c = A_a + A_b \]
Given \( A_b = 45 \): \[ A_c = A_a + 45 \]
Without the area of square A, we can't calculate a numeric value for \( A_c \).
However, if you have a specific value for \( A_a \), you can substitute it in: \[ A_c = A_a + 45 \]
Thus, the final area of square C in terms of the known area will remain \( A_a + 45 \) units squared. If \( A_a \) is provided, you can determine \( A_c \) accordingly.
If there's more context or specifics for square A's area, please provide that for a more conclusive answer!