The strength of the stimulus applied to the sensory receptor.

The amount of neurotransmitter released by the sensory neuron.
• The depolarization at the interneuron's cell body.
All of the above play a role in determining the frequency of action potentials in the axon of the interneuron.

1 answer

You are correct in stating that all of the factors you mentioned play a role in determining the frequency of action potentials in the axon of the interneuron. Here's a brief explanation of how each factor contributes:

  1. The strength of the stimulus applied to the sensory receptor: The strength of the stimulus influences the degree of depolarization of the sensory receptor. A stronger stimulus results in a larger receptor potential, leading to a higher frequency of action potentials being generated in the sensory neuron as it reaches the threshold more quickly and more frequently.

  2. The amount of neurotransmitter released by the sensory neuron: The amount of neurotransmitter released at the synapse between the sensory neuron and the interneuron affects the generation of action potentials in the interneuron. More neurotransmitter can lead to a greater postsynaptic potential in the interneuron, increasing the likelihood that it will reach its action potential threshold and fire more frequently.

  3. The depolarization at the interneuron's cell body: The degree of depolarization at the interneuron's cell body directly correlates with its ability to generate action potentials. If the depolarization is strong enough to reach the threshold, the interneuron will fire action potentials. Additionally, the degree and duration of depolarization affect the frequency of these spikes.

Therefore, the interplay between the stimulus strength, neurotransmitter release, and the resulting depolarization at the interneuron's cell body are all crucial for the modulation of action potential frequency in the interneuron's axon.