Use the substitution method to solve the system x=y−4 , x+8y=2 .(1 point)

Responses

(23,−313)
left parenthesis Start Fraction 2 over 3 End Fraction comma negative 3 Start Fraction 1 over 3 End Fraction right parenthesis

(−313,23)
left parenthesis negative 3 Start Fraction 1 over 3 End Fraction comma Start Fraction 2 over 3 End Fraction right parenthesis

no solution
no solution

infinite solutions

1 answer

To solve the system of equations using the substitution method, we start with the two equations:

  1. \( x = y - 4 \)
  2. \( x + 8y = 2 \)

Step 1: Substitute \( x \) in the second equation.

Using the first equation, we can substitute \( x \) in the second equation:

\[ (y - 4) + 8y = 2 \]

Step 2: Simplify the equation.

Now, combine like terms and simplify:

\[ y - 4 + 8y = 2 \ 9y - 4 = 2 \]

Step 3: Solve for \( y \).

Add 4 to both sides:

\[ 9y = 6 \]

Now, divide by 9:

\[ y = \frac{6}{9} = \frac{2}{3} \]

Step 4: Substitute \( y \) back to find \( x \).

Now that we have \( y \), we substitute back to find \( x \):

\[ x = y - 4 \ x = \frac{2}{3} - 4 \ x = \frac{2}{3} - \frac{12}{3} = \frac{2 - 12}{3} = \frac{-10}{3} \]

Final Solution:

Thus, the solution to the system is

\[ \left( -\frac{10}{3}, \frac{2}{3} \right) \]

This corresponds to the third response option from your list:

\[ \left( -3 \frac{1}{3}, \frac{2}{3} \right) \]

So the answer is:

\[ \text{(−}3 \frac{1}{3}, \frac{2}{3}\text{)} \]

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