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The fifth term of an exponential sequence is 4375 and the second term is 35. Find a) the third term. b) the sixth term. c)sum o...Question
The fifth term of an exponential sequence is 475 and the second term is 35 fine
The third term
The sixth term
Sum of the first five term
The third term
The sixth term
Sum of the first five term
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GPT-4o mini
In an exponential sequence, each term can be expressed as:
\[
a_n = a_1 \cdot r^{n-1}
\]
where \( a_n \) is the \( n \)-th term, \( a_1 \) is the first term, \( r \) is the common ratio, and \( n \) is the term number.
From the information provided:
- The fifth term (\( a_5 \)) is 475.
- The second term (\( a_2 \)) is 35.
Using the definition of an exponential sequence, we have:
\[
a_5 = a_1 \cdot r^{4} = 475
\]
\[
a_2 = a_1 \cdot r^{1} = 35
\]
Now we can express \( a_1 \) in terms of \( r \):
\[
a_1 = \frac{35}{r}
\]
Next, substitute this expression for \( a_1 \) into the equation for \( a_5 \):
\[
475 = \left(\frac{35}{r}\right) \cdot r^{4}
\]
This simplifies to:
\[
475 = 35r^{3}
\]
Solving for \( r^{3} \):
\[
r^{3} = \frac{475}{35}
\]
Calculating the fraction:
\[
r^{3} = 13.57142857 \quad (\text{approx. } 13.57)
\]
To find \( r \):
\[
r = \sqrt[3]{13.57142857} \approx 2.4027
\]
Now we can calculate \( a_1 \):
\[
a_1 = \frac{35}{r} \approx \frac{35}{2.4027} \approx 14.591
\]
### Finding the third term
The third term (\( a_3 \)) is given by:
\[
a_3 = a_1 \cdot r^{2}
\]
Calculating \( a_3 \):
\[
a_3 \approx 14.591 \cdot (2.4027)^2 \approx 14.591 \cdot 5.7757 \approx 84.36
\]
### Finding the sixth term
The sixth term (\( a_6 \)) can be calculated using:
\[
a_6 = a_1 \cdot r^{5}
\]
Calculating \( a_6 \):
\[
a_6 \approx 14.591 \cdot (2.4027)^5 \approx 14.591 \cdot 61.5081 \approx 897.06
\]
### Sum of the first five terms
The sum of the first five terms (\( S_5 \)) in an exponential sequence can be calculated using the formula:
\[
S_5 = a_1 \frac{r^5 - 1}{r - 1}
\]
Calculating \( S_5 \):
\[
S_5 \approx 14.591 \cdot \frac{(2.4027)^5 - 1}{2.4027 - 1} \approx 14.591 \cdot \frac{61.5081 - 1}{1.4027} \approx 14.591 \cdot \frac{60.5081}{1.4027} \approx 14.591 \cdot 43.1559 \approx 630.75
\]
### Summary of Results
- The third term (\( a_3 \)) is approximately **84.36**.
- The sixth term (\( a_6 \)) is approximately **897.06**.
- The sum of the first five terms (\( S_5 \)) is approximately **630.75**.
\[
a_n = a_1 \cdot r^{n-1}
\]
where \( a_n \) is the \( n \)-th term, \( a_1 \) is the first term, \( r \) is the common ratio, and \( n \) is the term number.
From the information provided:
- The fifth term (\( a_5 \)) is 475.
- The second term (\( a_2 \)) is 35.
Using the definition of an exponential sequence, we have:
\[
a_5 = a_1 \cdot r^{4} = 475
\]
\[
a_2 = a_1 \cdot r^{1} = 35
\]
Now we can express \( a_1 \) in terms of \( r \):
\[
a_1 = \frac{35}{r}
\]
Next, substitute this expression for \( a_1 \) into the equation for \( a_5 \):
\[
475 = \left(\frac{35}{r}\right) \cdot r^{4}
\]
This simplifies to:
\[
475 = 35r^{3}
\]
Solving for \( r^{3} \):
\[
r^{3} = \frac{475}{35}
\]
Calculating the fraction:
\[
r^{3} = 13.57142857 \quad (\text{approx. } 13.57)
\]
To find \( r \):
\[
r = \sqrt[3]{13.57142857} \approx 2.4027
\]
Now we can calculate \( a_1 \):
\[
a_1 = \frac{35}{r} \approx \frac{35}{2.4027} \approx 14.591
\]
### Finding the third term
The third term (\( a_3 \)) is given by:
\[
a_3 = a_1 \cdot r^{2}
\]
Calculating \( a_3 \):
\[
a_3 \approx 14.591 \cdot (2.4027)^2 \approx 14.591 \cdot 5.7757 \approx 84.36
\]
### Finding the sixth term
The sixth term (\( a_6 \)) can be calculated using:
\[
a_6 = a_1 \cdot r^{5}
\]
Calculating \( a_6 \):
\[
a_6 \approx 14.591 \cdot (2.4027)^5 \approx 14.591 \cdot 61.5081 \approx 897.06
\]
### Sum of the first five terms
The sum of the first five terms (\( S_5 \)) in an exponential sequence can be calculated using the formula:
\[
S_5 = a_1 \frac{r^5 - 1}{r - 1}
\]
Calculating \( S_5 \):
\[
S_5 \approx 14.591 \cdot \frac{(2.4027)^5 - 1}{2.4027 - 1} \approx 14.591 \cdot \frac{61.5081 - 1}{1.4027} \approx 14.591 \cdot \frac{60.5081}{1.4027} \approx 14.591 \cdot 43.1559 \approx 630.75
\]
### Summary of Results
- The third term (\( a_3 \)) is approximately **84.36**.
- The sixth term (\( a_6 \)) is approximately **897.06**.
- The sum of the first five terms (\( S_5 \)) is approximately **630.75**.
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