What are the odds against choosing a blue or green marble from a bag that contains two blue marbles, one green marble, seven white marbles, and four red marbles?

A. 5:14
B. 3:14
C. 3:11
D. 11:3
Best answer

1 answer

To solve the problem, we first need to determine the total number of marbles in the bag and the number of favorable outcomes for choosing a blue or green marble.

  1. Count the marbles:

    • Blue marbles: 2
    • Green marbles: 1
    • White marbles: 7
    • Red marbles: 4

    Total number of marbles = 2 (blue) + 1 (green) + 7 (white) + 4 (red) = 14 marbles.

  2. Count the favorable outcomes:

    • Favorable outcomes (blue or green) = 2 (blue) + 1 (green) = 3 marbles.
  3. Count the unfavorable outcomes:

    • Non-blue and non-green marbles (white and red) = 7 (white) + 4 (red) = 11 marbles.
  4. Calculate the odds against choosing a blue or green marble:

    • The odds against an event is the ratio of unfavorable outcomes to favorable outcomes.
    • Unfavorable outcomes = 11
    • Favorable outcomes = 3

    Therefore, the odds against choosing a blue or green marble is \( 11:3 \).

Thus, the answer is D. 11:3.