Use the equation y - 5 = x/3 to fill in the missing values in the table below. When I put BLANK, it means that part of the equation is blank and you need to fill it in.

To fill in the missing values in the table using the equation \( y - 5 = \frac{x}{3} \), we'll rearrange the equation to express \( y \) in terms of \( x \):

\[
y = \frac{x}{3} + 5
\]

Now we can calculate the missing values based on the given \( x \) and \( y \) values.

1. **For \( y = 1 \)**:
\[
1 = \frac{x}{3} + 5
\]
Subtract 5 from both sides:
\[
1 - 5 = \frac{x}{3} \implies -4 = \frac{x}{3}
\]
Multiply by 3:
\[
x = -12
\]

So, the first row is \( x: -12, y: 1 \).

2. **For \( x = -3 \)**, find \( y \):
\[
y = \frac{-3}{3} + 5 = -1 + 5 = 4
\]
This confirms the value is correct.

3. **For \( x = 0 \)**, find \( y \):
\[
y = \frac{0}{3} + 5 = 0 + 5 = 5
\]

So, the third row is \( x: 0, y: 5 \).

4. **For \( x = 6 \)**, find \( y \):
\[
y = \frac{6}{3} + 5 = 2 + 5 = 7
\]

So, the fourth row is \( x: 6, y: 7 \).

5. **For \( y = 8 \)**:
\[
8 = \frac{x}{3} + 5
\]
Subtract 5 from both sides:
\[
8 - 5 = \frac{x}{3} \implies 3 = \frac{x}{3}
\]
Multiply by 3:
\[
x = 9
\]

So, the last row is \( x: 9, y: 8 \).

Now, compiling everything, the table looks like this:

- \( x: -12, y: 1 \)
- \( x: -3, y: 4 \)
- \( x: 0, y: 5 \)
- \( x: 6, y: 7 \)
- \( x: 9, y: 8 \)

Here are the missing values:

\[
\text{First Row: } x = -12 \\
\text{Third Row: } y = 5 \\
\text{Fourth Row: } y = 7 \\
\text{Fifth Row: } x = 9
\]